Exact Examples: Alg. 2: y > 4x − 3 y ≥ −2x + 3 When you copy and paste the link below into your url it shows you how to graph the two equations above. Go to page 3 problem number 1. Link to graph:link
SAT: 8-2x< 6 -8 ; -8 (Subtract 8 on both sides of the inequality sign) -2x < -2 / -2 [ x>1 ]
Real-Life: Debbie has at most $60 to spend on clothes. She wants to buy a pair of jeans for $22 and spend the rest on t-shirts. Each t-shirt cost $8. By looking at the problem you know that the inequality has to have a less than or equal to sign because the shirt and jeans all together can’t be more than $60, but can be equal to that amount. The inequality would be $22+8x$60.
Create Your Own: First Problem Second Problem 1.) 4x+5>x-7 -5 -5 (subtract 5 on both sides of the inequalities) 4x>x-12 -x -x 3x >-12 _ 3 x>-4
2.) 3<3x-1<5 +1 +1 +1 4<3x<6 ---------- 3 4/3<x<2
Some skills you must have when starting unit 7 inequalities is knowing the difference between your greater than, less than, or equal to signs. At the end of this unit you should be able to solve for x. Some key pieces of new information that are presented in this unit are when you're dividing you have to change the sign which people tend to forget about. Some key misconceptions to look out for are when you’re doing a word problem. For example: If a word problem says Sarah has a maximum of $70 to spend. She wants to spend $30 on clothes and she wants to buy a pair of sneakers for $20 and use the rest for earrings. Earrings cost $4 a pack. Write out an inequality that Sarah can use to show her mom her spending's. Also find out the maximum packs of earrings that Sarah can purchase. Using the variable of x as her unknown value until solved.
Ex. 70>30+20+4x & Sarah can purchase 5 earrings at max. 70>30+20+4(5) 70> 50 + 20 70>70
Exact Examples:
Alg. 2: y > 4x − 3
y ≥ −2x + 3
When you copy and paste the link below into your url it shows you how to graph the two equations above. Go to page 3 problem number 1.
Link to graph: link
SAT:
8-2x< 6
-8 ; -8 (Subtract 8 on both sides of the inequality sign)
-2x < -2 / -2
[ x>1 ]
Real-Life: Debbie has at most $60 to spend on clothes. She wants to buy a pair of jeans for $22 and spend the rest on t-shirts. Each t-shirt cost $8.
By looking at the problem you know that the inequality has to have a less than or equal to sign because the shirt and jeans all together can’t be more than $60, but can be equal to that amount. The inequality would be $22+8x$60.
Create Your Own:
First Problem Second Problem
1.)
4x+5>x-7
-5 -5 (subtract 5 on both sides of the inequalities)
4x>x-12
-x -x
3x >-12 _
3
x>-4
2.)
3<3x-1<5
+1 +1 +1
4<3x<6
----------
3
4/3<x<2
Some skills you must have when starting unit 7 inequalities is knowing the difference between your greater than, less than, or equal to signs. At the end of this unit you should be able to solve for x. Some key pieces of new information that are presented in this unit are when you're dividing you have to change the sign which people tend to forget about. Some key misconceptions to look out for are when you’re doing a word problem. For example: If a word problem says Sarah has a maximum of $70 to spend. She wants to spend $30 on clothes and she wants to buy a pair of sneakers for $20 and use the rest for earrings. Earrings cost $4 a pack. Write out an inequality that Sarah can use to show her mom her spending's. Also find out the maximum packs of earrings that Sarah can purchase. Using the variable of x as her unknown value until solved.
Ex.
70>30+20+4x & Sarah can purchase 5 earrings at max.
70>30+20+4(5)
70> 50 + 20
70>70